[PATCH v6 1/1] PRUSS UIO driver support
Thomas Gleixner
tglx at linutronix.de
Tue Mar 1 04:51:43 EST 2011
On Tue, 1 Mar 2011, Pratheesh Gangadhar wrote:
> +
> +static spinlock_t lock;
static DEFINE_SPINLOCK(lock);
> +static struct clk *pruss_clk;
> +static struct uio_info *info;
> +static dma_addr_t sram_paddr, ddr_paddr;
> +static void *prussio_vaddr, *sram_vaddr, *ddr_vaddr;
> +
> +static irqreturn_t pruss_handler(int irq, struct uio_info *dev_info)
> +{
> + unsigned long flags;
> + int val, intr_mask = (1 << (irq - 1));
> + void __iomem *base = dev_info->mem[0].internal_addr;
> + void __iomem *intren_reg = base + PINTC_HIER;
> + void __iomem *intrstat_reg = base + PINTC_HIPIR + ((irq - 1) << 2);
> +
> + spin_lock_irqsave(&lock, flags);
spin_lock() is enough as we run handlers with interrupts disabled.
> + val = ioread32(intren_reg);
> + /* Is interrupt enabled and active ? */
> + if (!(val & intr_mask) && (ioread32(intrstat_reg) & HIPIR_NOPEND)) {
> + spin_unlock_irqrestore(&lock, flags);
> + return IRQ_NONE;
> + }
> +
> + /* Disable interrupt */
> + iowrite32((val & ~intr_mask), intren_reg);
> + spin_unlock_irqrestore(&lock, flags);
> + return IRQ_HANDLED;
> +}
So now you still have not solved the problem of user space enabling an
interrupt again. That's racy as well and you can solve it by providing
an uio->irq_control function which handles the interrupt enable
register under the lock as well.
Thanks,
tglx
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