[rtc-linux] [PATCH v3] rtc: snvs: add Freescale rtc-snvs driver
Lothar Waßmann
LW at KARO-electronics.de
Thu Aug 16 04:08:04 EDT 2012
Hi,
Andrew Morton writes:
> On Wed, 15 Aug 2012 22:16:10 +0800
> Shawn Guo <shawn.guo at linaro.org> wrote:
>
> > Thanks for looking at the patch, Andrew.
> >
> > On Tue, Aug 14, 2012 at 05:03:00PM -0700, Andrew Morton wrote:
> > > On Fri, 13 Jul 2012 15:31:03 +0800
> > > Shawn Guo <shawn.guo at linaro.org> wrote:
> > >
> > > > +static int snvs_rtc_enable(struct snvs_rtc_data *data, bool enable)
> > > > +{
> > > > + unsigned long timeout = jiffies + msecs_to_jiffies(1);
> > > > + unsigned long flags;
> > > > + u32 lpcr;
> > > > +
> > > > + spin_lock_irqsave(&data->lock, flags);
> > > > +
> > > > + lpcr = readl(data->ioaddr + SNVS_LPCR);
> > > > + if (enable)
> > > > + lpcr |= SNVS_LPCR_SRTC_ENV;
> > > > + else
> > > > + lpcr &= ~SNVS_LPCR_SRTC_ENV;
> > > > + writel(lpcr, data->ioaddr + SNVS_LPCR);
> > > > +
> > > > + spin_unlock_irqrestore(&data->lock, flags);
> > > > +
> > > > + while (1) {
> > > > + lpcr = readl(data->ioaddr + SNVS_LPCR);
> > > > +
> > > > + if (enable) {
> > > > + if (lpcr & SNVS_LPCR_SRTC_ENV)
> > > > + break;
> > > > + } else {
> > > > + if (!(lpcr & SNVS_LPCR_SRTC_ENV))
> > > > + break;
> > > > + }
> > > > +
> > > > + if (time_after(jiffies, timeout))
> > > > + return -ETIMEDOUT;
> > > > + }
> > > > +
> > > > + return 0;
> > > > +}
> > >
> > > The timeout code here is fragile. If acquiring the spinlock takes more
> > > than a millisecond or if this thread gets interrupted or preempted then
> > > we could easily execute that loop just a single time, and fail.
> > >
> > So what about moving the timeout initialization to right above the
> > while(1) loop?
>
> It still has the same problem - a well-timed preemption would cause a
> timeout.
>
> > > It would be better to retry a fixed number of times, say 1000? That
> > > would take around 1 millisecond, but might be overkill.
> > >
> > How long a 1000 times loop takes really depends on the cpu frequency,
> > right?
>
> No, it will depend on the preiod of that readl(), which typically takes
> much much longer than a cpu cycle. It depends a lot on the bus type
> but I'd guess that the readl would take 100's of nanoseconds. Thus we
> can use the expected readl duration to control the timeout interval.
>
Why not read the register once more in case of a timeout, which
would guarantee to have a current view of the register contents no
matter how long the process may have been descheduled before:
[...]
static int snvs_rtc_enable_done(int enable, void __iomem *addr)
{
u32 lpcr = readl(addr + SNVS_LPCR);
return !!enable ^ !(lpcr & SNVS_LPCR_SRTC_ENV);
}
[...]
while (1) {
if (svns_rtc_enable_done(enable, data->ioaddr))
break;
if (time_after(jiffies, timeout)) {
if (!svns_rtc_enable_done(enable, data->ioaddr))
return -ETIMEDOUT;
}
}
Lothar Waßmann
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