[Linux-parport] [patch 2/4] block/pg: replace pg_sleep() with
msleep()
domen at coderock.org
domen at coderock.org
Sat Mar 5 17:44:54 EST 2005
Use msleep()/ssleep() instead of pg_sleep() to guarantee
the task delays as expected. TASK_INTERRUPTIBLE is used in the original code,
however there is no check on the return values / for signals, thus I believe
TASK_UNINTERRUPTIBLE (and hence msleep()) is more appropriate. Change pg_sleep()
to use TASK_UNINTERRUPTIBLE as well.
Signed-off-by: Nishanth Aravamudan <nacc at us.ibm.com>
Signed-off-by: Domen Puncer <domen at coderock.org>
---
kj-domen/drivers/block/paride/pg.c | 4 ++--
1 files changed, 2 insertions(+), 2 deletions(-)
diff -puN drivers/block/paride/pg.c~msleep-drivers_block_paride_pg drivers/block/paride/pg.c
--- kj/drivers/block/paride/pg.c~msleep-drivers_block_paride_pg 2005-03-05 16:10:46.000000000 +0100
+++ kj-domen/drivers/block/paride/pg.c 2005-03-05 16:10:46.000000000 +0100
@@ -295,7 +295,7 @@ static inline u8 DRIVE(struct pg *dev)
static void pg_sleep(int cs)
{
- current->state = TASK_INTERRUPTIBLE;
+ set_current_state(TASK_UNINTERRUPTIBLE);
schedule_timeout(cs);
}
@@ -409,7 +409,7 @@ static int pg_reset(struct pg *dev)
write_reg(dev, 6, DRIVE(dev));
write_reg(dev, 7, 8);
- pg_sleep(20 * HZ / 1000);
+ msleep(20);
k = 0;
while ((k++ < PG_RESET_TMO) && (status_reg(dev) & STAT_BUSY))
_
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