[PATCH -next] jffs2: fix use-after-free in jffs2_clear_xattr_subsystem
libaokun (A)
libaokun1 at huawei.com
Wed Mar 16 18:29:11 PDT 2022
在 2022/3/17 6:01, Richard Weinberger 写道:
> ----- Ursprüngliche Mail -----
>> Von: "libaokun" <libaokun1 at huawei.com>
>> An: "richard" <richard at nod.at>, "David Woodhouse" <dwmw2 at infradead.org>, "christian brauner"
>> <christian.brauner at ubuntu.com>, "linux-mtd" <linux-mtd at lists.infradead.org>, "linux-kernel"
>> <linux-kernel at vger.kernel.org>
>> CC: "yukuai3" <yukuai3 at huawei.com>, "stable" <stable at vger.kernel.org>, "Hulk Robot" <hulkci at huawei.com>, "libaokun"
>> <libaokun1 at huawei.com>
>> Gesendet: Donnerstag, 10. März 2022 09:35:18
>> Betreff: Re: [PATCH -next] jffs2: fix use-after-free in jffs2_clear_xattr_subsystem
>> A gentle ping, sorry for the noise.
>>
>> 在 2021/12/28 20:54, Baokun Li 写道:
>>> When we mount a jffs2 image, assume that the first few blocks of
>>> the image are normal and contain at least one xattr-related inode,
>>> but the next block is abnormal. As a result, an error is returned
>>> in jffs2_scan_eraseblock(). jffs2_clear_xattr_subsystem() is then
>>> called in jffs2_build_filesystem() and then again in
>>> jffs2_do_fill_super().
>>>
>>> Finally we can observe the following report:
>>> ==================================================================
>>> BUG: KASAN: use-after-free in jffs2_clear_xattr_subsystem+0x95/0x6ac
>>> Read of size 8 at addr ffff8881243384e0 by task mount/719
>>>
>>> Call Trace:
>>> dump_stack+0x115/0x16b
>>> jffs2_clear_xattr_subsystem+0x95/0x6ac
>>> jffs2_do_fill_super+0x84f/0xc30
>>> jffs2_fill_super+0x2ea/0x4c0
>>> mtd_get_sb+0x254/0x400
>>> mtd_get_sb_by_nr+0x4f/0xd0
>>> get_tree_mtd+0x498/0x840
>>> jffs2_get_tree+0x25/0x30
>>> vfs_get_tree+0x8d/0x2e0
>>> path_mount+0x50f/0x1e50
>>> do_mount+0x107/0x130
>>> __se_sys_mount+0x1c5/0x2f0
>>> __x64_sys_mount+0xc7/0x160
>>> do_syscall_64+0x45/0x70
>>> entry_SYSCALL_64_after_hwframe+0x44/0xa9
>>>
>>> Allocated by task 719:
>>> kasan_save_stack+0x23/0x60
>>> __kasan_kmalloc.constprop.0+0x10b/0x120
>>> kasan_slab_alloc+0x12/0x20
>>> kmem_cache_alloc+0x1c0/0x870
>>> jffs2_alloc_xattr_ref+0x2f/0xa0
>>> jffs2_scan_medium.cold+0x3713/0x4794
>>> jffs2_do_mount_fs.cold+0xa7/0x2253
>>> jffs2_do_fill_super+0x383/0xc30
>>> jffs2_fill_super+0x2ea/0x4c0
>>> [...]
>>>
>>> Freed by task 719:
>>> kmem_cache_free+0xcc/0x7b0
>>> jffs2_free_xattr_ref+0x78/0x98
>>> jffs2_clear_xattr_subsystem+0xa1/0x6ac
>>> jffs2_do_mount_fs.cold+0x5e6/0x2253
>>> jffs2_do_fill_super+0x383/0xc30
>>> jffs2_fill_super+0x2ea/0x4c0
>>> [...]
>>>
>>> The buggy address belongs to the object at ffff8881243384b8
>>> which belongs to the cache jffs2_xattr_ref of size 48
>>> The buggy address is located 40 bytes inside of
>>> 48-byte region [ffff8881243384b8, ffff8881243384e8)
>>> [...]
>>> ==================================================================
>>>
>>> The triggering of the BUG is shown in the following stack:
>>> -----------------------------------------------------------
>>> jffs2_fill_super
>>> jffs2_do_fill_super
>>> jffs2_do_mount_fs
>>> jffs2_build_filesystem
>>> jffs2_scan_medium
>>> jffs2_scan_eraseblock <--- ERROR
>>> jffs2_clear_xattr_subsystem <--- free
>>> jffs2_clear_xattr_subsystem <--- free again
>>> -----------------------------------------------------------
>>>
>>> An error is returned in jffs2_do_mount_fs(). If the error is returned
>>> by jffs2_sum_init(), the jffs2_clear_xattr_subsystem() does not need to
>>> be executed. If the error is returned by jffs2_build_filesystem(), the
>>> jffs2_clear_xattr_subsystem() also does not need to be executed again.
>>> So move jffs2_clear_xattr_subsystem() from 'out_inohash' to 'out_root'
>>> to fix this UAF problem.
>>>
>>> Fixes: aa98d7cf59b5 ("[JFFS2][XATTR] XATTR support on JFFS2 (version. 5)")
>>> Cc: stable at vger.kernel.org
>>> Reported-by: Hulk Robot <hulkci at huawei.com>
>>> Signed-off-by: Baokun Li <libaokun1 at huawei.com>
> Applied. Thanks for fixing!
>
> Thanks,
> //richard
> .
Thank you for your review!
--
With Best Regards,
Baokun Li
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