[PATCH] RFC: interrupt consistency check for OF GPIO IRQs
Alexander Holler
holler at ahsoftware.de
Thu Sep 12 07:09:44 EDT 2013
Am 12.09.2013 12:28, schrieb Alexander Holler:
> Am 12.09.2013 12:11, schrieb Javier Martinez Canillas:
>> On 09/12/2013 10:55 AM, Alexander Holler wrote:
>
> ...
>>>
>>> By the way, how do you define two GPIOs/IRQs from different
>>> gpio-banks/irq-controllers wuth that scheme?
>>>
>>
>> That is indeed a very good question and I don't have a definite answer.
>>
>>> Would that be like below?
>>>
>>> ethernet at 5,0 {
>>> compatible = "smsc,lan9221", "smsc,lan9115";
>>> interrupt-parent = <&gpio6>;
>>> interrupts = <16 8>;
>>> interrupt-parent = <&gpio7>;
>>> interrupts = <1 IRQF_TRIGGER_FALLING>; /* GPIO7_1 */
>>> };
>>>
>
> ...
>
>> So, if I understood the code correctly the DT IRQ core doesn't expect
>> a device
>> node to have more than one "interrupt-parent" property.
>>
>> It *should* work though if you have multiple "interrupts" properties
>> defined and
>> all of them have the same "interrupt-parent":
>>
>> interrupt-parent = <&gpio6>;
>> interrupts = <1 IRQF_TRIGGER_HIGH>; /* GPIO6_1 */
>> interrupts = <2 IRQF_TRIGGER_LOW>; /* GPIO6_2 */
>>
>> since of_irq_map_one() will be called for each "interrupts" and the
>> correct
>> "interrupt-parent" will get obtained by of_irq_find_parent().
>
> I assumed that answer. So to make such a scenario possible, something
> like this might be neccessary:
>
> interrupts = <&gpio6 1 IRQF_TRIGGER_HIGH>; /* GPIO6_1 */
> interrupts = <&gpio7 2 IRQF_TRIGGER_LOW>; /* GPIO7_2 */
>
> or, to be compatible
>
> interrupts = <1 IRQF_TRIGGER_HIGH &gpio6>; /* GPIO6_1 */
> interrupts = <1 IRQF_TRIGGER_LOW &gpio7>; /* GPIO7_1 */
>
> Another problem is the naming. In all the above cases, the driver would
> not know which IRQ he should use for what. Maybe the order defines it,
> but that wouldn't be very verbose. And I think just changing the name
> would make travelling the tree impossible, as only the driver itself
> would know the name and it's meaning.
On a second look, travelling the tree is still possible if the solution
would be like above (without that interrupt-parent). So if a driver
requires two interrupts he could use
interrupt-foo = <1 IRQF_TRIGGER_HIGH &gpio6>; /* GPIO6_1 */
interrupt-bar = <1 IRQF_TRIGGER_LOW &gpio7>; /* GPIO7_1 */
And travelling the tree will still be possible because walking from the
interrupt-controllers (those gpio) downwards would end up at the
interrupt definitions, so the name of them isn't needed to find them in
the tree.
Regards,
Alexander Holler
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