[PATCH 1/2] Initial support for Allwinner's Security ID fuses
Oliver Schinagl
oliver+list at schinagl.nl
Sat May 25 15:25:51 EDT 2013
On 05/25/13 14:22, Maxime Ripard wrote:
> Hi Oliver,
>
> On Fri, May 24, 2013 at 11:50:38PM +0200, Oliver Schinagl wrote:
>> On 05/18/13 19:19, Oliver Schinagl wrote:
>> <snip>
>>>>> +
>>>>> +
>>>>> +/* We read the entire key, using a look up table. Returned is only the
>>>>> + * requested byte. This is of course slower then it could be and uses 4 times
>>>>> + * more reads as needed but keeps code a little simpler.
>>>>> + */
>>>>> +u8 sunxi_sid_read_byte(const int key)
>>>>> +{
>>>>> + u32 sid_key;
>>>>> + u8 ret;
>>>>> +
>>>>> + ret = 0;
>>>>> + if (likely((key <= SUNXI_SID_SIZE))) {
>>>>> + sid_key = ioread32(p->sid_base + keys_lut[key >> 2]);
>>>>> + switch (key % 4) {
>>>>> + case 0:
>>>>> + ret = (sid_key >> 24) & 0xff;
>>>>> + break;
>>>>> + case 1:
>>>>> + ret = (sid_key >> 16) & 0xff;
>>>>> + break;
>>>>> + case 2:
>>>>> + ret = (sid_key >> 8) & 0xff;
>>>>> + break;
>>>>> + case 3:
>>>>> + ret = sid_key & 0xff;
>>>>> + break;
>>>>> + }
>>>>> + }
>>>>
>>>> Come on, you can do better. This lookup table is useless.
>>> I didn't want to depend on the fixed layout of memory, but consider it
>>> removed.
>> But i'm not smart enough :p
>>
>> We can either use the look up table (which does have benefits as its
>> potentially more future proof), or do some ((key >> 2) << 2) to
>> 'drop' the LSB's that we want to ignore (unless there's some smarter
>> way).
>>
>> Personally, I think the LUT is a little cleaner and more readable,
>> but I guess if you look at poor efficiency, the lut costs some
>> memory, the left/right shift cost an additional >> 2 ... what you
>> prefer.
>
> What about:
>
> val = ioread32be(base + (key / 4));
> val >>= (key % 4) * 8;
> return val & 0xff;
>
> No lookup table, no weird swich statement, and you get the endianness
> conversion only when you need it.
Ok I think I like the Endianess, ioread32be does the right thing then?
I'll read up on that.
As for key / 4; how will that work without the lut?
Lets take byte 14 (out of the available 16). Byte 14 (0x0e) is located
in SID_KEY3, so base + 0x0c. We need to write a whole 32bit word to keep
with alignment, the registers go wakko if you do unaligned reads. So we
need to read the entire 32 bits, then find our byte.
key / 4 for 14 yields 0x03. So we have base + 0x03, which is not what we
want. We want base + 0x0c, which is either ((key >> 2) << 2)) Or, ((key
/ 4) * 4)) which to me, are both equally confusing. So we either use the
look up table, which is a little cleaner and is a bit more future proof
if either a) there's more 'eeprom like' storage which can be combined
herein or b) 'a' next version has non-continuing regions. Granted
neither is something to worry about right now.
Turl already mentioned the calculated shift, instead of the switch. I
agree to also like it better and have already rewritten that bit.
If I made a really stupid thinking mistake or my math is somehow wrong,
feel free to point it out :) I don't mind manning up to my mistakes :)
>
> Maxime
>
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