[PATCH v3 02/31] arm64: Kernel booting and initialisation
Jean-Christophe PLAGNIOL-VILLARD
plagnioj at jcrosoft.com
Mon Sep 10 01:53:39 EDT 2012
On 19:29 Sun 09 Sep , Nicolas Pitre wrote:
> On Sun, 9 Sep 2012, Jean-Christophe PLAGNIOL-VILLARD wrote:
>
> > On 17:26 Fri 07 Sep , Catalin Marinas wrote:
> > > +4. Call the kernel image
> > > +------------------------
> > > +
> > > +Requirement: MANDATORY
> > > +
> > > +The decompressed kernel image contains a 32-byte header as follows:
> > > +
> > > + u32 magic = 0x14000008; /* branch to stext, little-endian */
> > > + u32 res0 = 0; /* reserved */
> > > + u64 text_offset; /* Image load offset */
> > > + u64 res1 = 0; /* reserved */
> > > + u64 res2 = 0; /* reserved */
> > we need to have a magic to known it's a arm64 kernel
>
> You have it: it's 0x14000008 at the beginning.
fragile
>
> > > +
> > > +The image must be placed at the specified offset (currently 0x80000)
> > > +from the start of the system RAM and called there. The start of the
> > > +system RAM must be aligned to 2MB.
> > can we drop this
>
> Drop what?
> And why?
This contrain the must be loadable at any address
Best Regards,
J.
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