[PATCH] Allow memblock steal operations to remove memory from anywhere
Shilimkar, Santosh
santosh.shilimkar at ti.com
Sun Aug 12 08:46:57 EDT 2012
On Sun, Aug 12, 2012 at 4:27 PM, Russell King - ARM Linux
<linux at arm.linux.org.uk> wrote:
> Found this with the cubox, which wants to obtain large blocks of
> RAM for the GPU and VPU devices at boot time. I don't believe
> any other platforms care where the memory comes from, so I think
> this is safe.
>
Agree.
> However, OMAP and iMX folk should check this patch - thanks.
>
Works for OMAP without any issues.
Acked-by: Santosh Shilimkar <santosh.shilimkar at ti.com>
> 8<===
> From: Russell King <rmk+kernel at arm.linux.org.uk>
> Subject: ARM: Allow arm_memblock_steal() to remove memory from any RAM region
>
> Allow arm_memblock_steal() to remove memory from any RAM region,
> including highmem areas. This allows memory to be stolen from the
> very top of declared memory, including highmem areas, rather than
> our precious lowmem.
>
> Signed-off-by: Russell King <rmk+kernel at arm.linux.org.uk>
> ---
> arch/arm/mm/init.c | 2 +-
> 1 files changed, 1 insertions(+), 1 deletions(-)
>
> diff --git a/arch/arm/mm/init.c b/arch/arm/mm/init.c
> index f54d592..04632f3 100644
> --- a/arch/arm/mm/init.c
> +++ b/arch/arm/mm/init.c
> @@ -324,7 +324,7 @@ phys_addr_t __init arm_memblock_steal(phys_addr_t size, phys_addr_t align)
>
> BUG_ON(!arm_memblock_steal_permitted);
>
> - phys = memblock_alloc(size, align);
> + phys = memblock_alloc_base(size, align, MEMBLOCK_ALLOC_ANYWHERE);
> memblock_free(phys, size);
> memblock_remove(phys, size);
>
> --
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