Locking in the clk API, part 2: clk_prepare/clk_unprepare
Richard Zhao
linuxzsc at gmail.com
Fri Feb 4 07:45:34 EST 2011
On Tue, Feb 01, 2011 at 05:11:29PM +0800, Jeremy Kerr wrote:
> Hi all,
>
> > I suggested that clk_prepare() be callable only from non-atomic contexts,
> > and do whatever's required to ensure that the clock is available. That
> > may end up enabling the clock as a result.
>
> I think that clk_prepare/clk_unprepare looks like the most promising solution,
> so will try to get some preliminary patches done. Here's what I'm planning:
>
> -----
>
> The changes to the API are essentially:
>
> 1) Document clk_enable/clk_disable as callable from atomic contexts, and
> so clock implementations must not sleep within this function.
>
> 2) For clock implementations that may sleep to turn on a clock, we add a
> new pair of functions to the clock API: clk_prepare and clk_unprepare.
>
> These will provide hooks for the clock implmentation to do any sleepable
> work (eg, wait for PLLs to settle) in preparation for a later clk_enable.
>
> For the most common clock implemntation cases (where clocks can be enabled
> atomically), these functions will be a no-op, and all of the enable/disable
> work can be done in clk_enable/clk_disable.
>
> For implementations where clocks require blocking on enable/disable, most
> of the work will be done in clk_prepare/clk_unprepare. The clk_enable
> and clk_disable functions may be no-ops.
>
> For drivers, this means that clk_prepare must be called (and have returned)
> before calling clk_enable.
>
> == Enable/Prepare counts ==
>
> I intend to do the enable and prepare "counting" in the core clock API,
> meaning that that the clk_ops callbacks will only invoked on the first
> prepare/enable and the last unprepare/disable.
>
> == Concurrency ==
>
> Splitting the prepare and enable stages introduces the concurrency
> requirements:
>
> 1) clk_enable must not return before the clock is outputting a valid clock
> signal.
>
> 2) clk_prepare must not return before the clock is fully prepared (ie, it is
> safe to call clk_enable).
>
> It is not possible for clk_enable to wait for the clock to be prepared,
> because that would require synchronisation with clk_prepare, which may then
> require blocking. Therefore:
>
> 3) The clock consumer *must* respect the proper ordering of clk_prepare and
> clk_enable. For example, drivers that call clk_enable during an interrupt
> must ensure that the interrupt handler will not be invoked until
> clk_prepare has returned.
>
> == Other considerations ==
>
> The time that a clock spends "prepared" is a superset of the the time that a
> clock spends "enabled". Therefore, clocks that are switched on during
> clk_prepare (ie, non-atomic clocks) will be running for a larger amount of
> time. In some cases, this can be mitigated by moving some of the final
> (atomic) switching functionality to the clk_enable function.
>
> == Implementation ==
>
> Basically:
>
> struct clk {
> const struct clk_ops *ops
> int enable_count;
> spinlock_t enable_lock;
> int prepare_count;
> struct mutex prepare_lock;
> };
>
> int clk_enable(struct clk *clk)
> {
> int ret = 0;
>
> spin_lock(&clk->enable_lock);
> if (!clk->enable_count)
> ret = clk->ops->enable(clk);
>
> if (!ret)
> clk->enable_count++;
> spin_unlock(&clk->enable_lock);
>
> return ret;
> }
Why do we not call parent's clk_enable in this function? For flexible? How many
different cases is causing us to move the effert to platform clock driver?
>
> int clk_prepare(struct clk *clk)
> {
> int ret = 0;
>
> mutex_lock(&clk->prepare_lock);
> if (!clk->prepare_count)
> ret = clk->ops->prepare(clk);
>
> if (!ret)
> clk->prepare_count++;
> mutex_unlock(&clk->prepare_lock);
>
> return ret;
> }
Same as above.
And for most clocks, prepare/unprepare may be NULL. So in such case, is it
better to call parent's prepare and increase its own prepare_count here?
Thanks
Richard
>
> -----
>
> Comments welcome, code coming soon.
>
> Cheers,
>
>
> Jeremy
>
>
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