[PATCH rdma-next 00/13] Add RDMA inline crypto support

[Leon Romanovsky]

On Tue, Jan 17, 2023 at 10:47:44PM -0800, Eric Biggers wrote:
> Hi Leon,
> 
> On Mon, Jan 16, 2023 at 03:05:47PM +0200, Leon Romanovsky wrote:
> > >From Israel,
> > 
> > The purpose of this patchset is to add support for inline
> > encryption/decryption of the data at storage protocols like nvmf over
> > RDMA (at a similar way like integrity is used via unique mkey).
> > 
> > This patchset adds support for plaintext keys. The patches were tested
> > on BF-3 HW with fscrypt tool to test this feature, which showed reduce
> > in CPU utilization when comparing at 64k or more IO size. The CPU utilization
> > was improved by more than 50% comparing to the SW only solution at this case.
> > 
> > How to configure fscrypt to enable plaintext keys:
> >  # mkfs.ext4 -O encrypt /dev/nvme0n1
> >  # mount /dev/nvme0n1 /mnt/crypto -o inlinecrypt
> >  # head -c 64 /dev/urandom > /tmp/master_key
> >  # fscryptctl add_key /mnt/crypto/ < /tmp/master_key
> >  # mkdir /mnt/crypto/test1
> >  # fscryptctl set_policy 152c41b2ea39fa3d90ea06448456e7fb /mnt/crypto/test1
> >    ** “152c41b2ea39fa3d90ea06448456e7fb” is the output of the
> >       “fscryptctl add_key” command.
> >  # echo foo > /mnt/crypto/test1/foo
> > 
> > Notes:
> >  - At plaintext mode only, the user set a master key and the fscrypt
> >    driver derived from it the DEK and the key identifier.
> >  - 152c41b2ea39fa3d90ea06448456e7fb is the derived key identifier
> >  - Only on the first IO, nvme-rdma gets a callback to load the derived DEK. 
> > 
> > There is no special configuration to support crypto at nvme modules.
> > 
> > Thanks
> 
> Very interesting work!  Can you Cc me on future versions?

Sure

> 
> I'm glad to see that this hardware allows all 16 IV bytes to be specified.
> 
> Does it also handle programming and evicting keys efficiently?

"efficiently" is a very subjective term. We are using FW command
interface to program keys and this interface can do hundreds/thousands
commands per-second.

Thanks