JFFS2 and small sized flash chips

[Olof Backing]

Hello!
I found this code segement in fs.c for JFFS2:

if (c->flash_size < 5*c->sector_size) {
	printk(KERN_ERR "jffs2: Too few erase blocks (%d)\n", c->flash_size / c->sector_size);
	return -EINVAL;
}

This code states that it needs 5 erase blocks, right? Consider this table:

struct flash_info {
	char		*name;
	u8		id;
	u16		jedec_id;
	unsigned	sector_size;
	unsigned	n_sectors;
};

static struct flash_info __devinitdata m25p_data [] = {
	/* REVISIT: fill in JEDEC ids, for parts that have them */
	{ "m25p05", 0x05, 0x2010, 32 * 1024, 2 },
	{ "m25p10", 0x10, 0x2011, 32 * 1024, 4 },
	{ "m25p20", 0x11, 0x2012, 64 * 1024, 4 },
	{ "m25p40", 0x12, 0x2013, 64 * 1024, 8 },
	{ "m25p80", 0x13, 0x0000, 64 * 1024, 16 },
	{ "m25p16", 0x14, 0x2015, 64 * 1024, 32 },
	{ "m25p32", 0x15, 0x2016, 64 * 1024, 64 },
	{ "m25p64", 0x16, 0x2017, 64 * 1024, 128 },
};

Where I'm currently being offered an m25p10 for use. I have two simple qestions:

* Am I safe to use JFFS2 on that chip?
* Or is the m25p40 with 8 sectors the smallest chip leaving 8-5=3 sectors for
(payload) data?

Regards,
Olof
-- 
Olof Backing
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