[PATCH v2] GIC: Dont disable INT in ack callback

Jeff Ohlstein johlstei at codeaurora.org
Tue Jul 27 14:46:38 EDT 2010


From: Abhijeet Dharmapurikar <adharmap at codeaurora.org>

Unless gic_ack_irq is called from __do_IRQ, interrupt should not
be disabled in the ack function.

Signed-off-by: Abhijeet Dharmapurikar <adharmap at codeaurora.org>
Signed-off-by: Jeff Ohlstein <johlstei at codeaurora.org>
---
 arch/arm/common/gic.c |   15 ---------------
 1 files changed, 0 insertions(+), 15 deletions(-)

diff --git a/arch/arm/common/gic.c b/arch/arm/common/gic.c
index 337741f..9bc6d88 100644
--- a/arch/arm/common/gic.c
+++ b/arch/arm/common/gic.c
@@ -67,25 +67,10 @@ static inline unsigned int gic_irq(unsigned int irq)
 
 /*
  * Routines to acknowledge, disable and enable interrupts
- *
- * Linux assumes that when we're done with an interrupt we need to
- * unmask it, in the same way we need to unmask an interrupt when
- * we first enable it.
- *
- * The GIC has a separate notion of "end of interrupt" to re-enable
- * an interrupt after handling, in order to support hardware
- * prioritisation.
- *
- * We can make the GIC behave in the way that Linux expects by making
- * our "acknowledge" routine disable the interrupt, then mark it as
- * complete.
  */
 static void gic_ack_irq(unsigned int irq)
 {
-	u32 mask = 1 << (irq % 32);
-
 	spin_lock(&irq_controller_lock);
-	writel(mask, gic_dist_base(irq) + GIC_DIST_ENABLE_CLEAR + (gic_irq(irq) / 32) * 4);
 	writel(gic_irq(irq), gic_cpu_base(irq) + GIC_CPU_EOI);
 	spin_unlock(&irq_controller_lock);
 }
-- 
1.7.1.1

Sent by an employee of the Qualcomm Innovation Center, Inc.
The Qualcomm Innovation Center, Inc. is a member of the Code Aurora Forum.



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