[PATCH net 2/5] rxrpc: Fix use of wrong skb when comparing queued RESP challenge serial
Jakub Kicinski
kuba at kernel.org
Fri Mar 20 18:45:44 PDT 2026
Hi David!
The review under --- is AI generated. It looks legit to me.
The Google reviewer also points out preexiting problems that may be worth looking at:
https://sashiko.dev/#/patchset/20260319150150.4189381-1-dhowells%40redhat.com
For local reproduction steps see https://netdev-ai.bots.linux.dev/ai-local.html
---
rxrpc: Fix use of wrong skb when comparing queued RESP challenge serial
In rxrpc_post_response(), the code should be comparing the challenge
serial number from the cached response before deciding to switch to a
newer response, but looks at the newer packet private data instead,
rendering the comparison always false.
Fix this by switching to look at the older packet.
> diff --git a/net/rxrpc/conn_event.c b/net/rxrpc/conn_event.c
> index 98ad9b51ca2c..2c27f47951f9 100644
> --- a/net/rxrpc/conn_event.c
> +++ b/net/rxrpc/conn_event.c
> @@ -557,7 +557,7 @@ void rxrpc_post_response(struct rxrpc_connection *conn, struct sk_buff *skb)
> spin_lock_irq(&local->lock);
> old = conn->tx_response;
> if (old) {
> - struct rxrpc_skb_priv *osp = rxrpc_skb(skb);
> + struct rxrpc_skb_priv *osp = rxrpc_skb(old);
>
> /* Always go with the response to the most recent challenge. */
> if (after(sp->resp.challenge_serial, osp->resp.challenge_serial))
> conn->tx_response = old;
^^^^
Does this have the logic inverted? The comment says "Always go with
the response to the most recent challenge" and the condition checks
if the new response has a more recent serial number:
if (after(sp->resp.challenge_serial, osp->resp.challenge_serial))
When this is TRUE (new serial is after old serial), the code keeps
the OLD response by setting conn->tx_response = old. Shouldn't it
keep the NEW response instead? Something like:
if (after(sp->resp.challenge_serial, osp->resp.challenge_serial))
conn->tx_response = skb;
This would cause the connection to respond to outdated challenges
rather than the most recent one.
> else
> old = skb;
When a new response is rejected here (because the old response has a
more recent challenge serial), what happens to the rejected packet?
The function assigns it to the local variable 'old' but never frees
it.
Looking at the callers:
- rxkad_respond_to_challenge() in rxkad.c sets response = NULL after
calling this function
- rxgk_construct_response() in rxgk.c does the same
This suggests ownership transfers to rxrpc_post_response(). Should
the rejected packet be freed with rxrpc_free_skb() before returning?
> } else {
> conn->tx_response = skb;
> }
> spin_unlock_irq(&local->lock);
> rxrpc_poke_conn(conn, rxrpc_conn_get_poke_response);
> }
--
pw-bot: cr
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