[Linux-parport] [PATCH] ppdev: fix double-free of pp->pdev->name
jann at thejh.net
Sun Oct 30 09:47:35 PDT 2016
On Sun, Oct 30, 2016 at 09:29:10AM -0700, Andy Lutomirski wrote:
> On Sun, Oct 30, 2016 at 8:44 AM, Jann Horn <jann at thejh.net> wrote:
> > free_pardevice() is called by parport_unregister_device() and already frees
> > pp->pdev->name, don't try to do it again.
> > This bug causes kernel crashes.
> > I found and verified this with KASAN and some added pr_emerg()s:
> > [ 60.316568] pp_release: pp->pdev->name == ffff88039cb264c0
> > [ 60.316692] free_pardevice: freeing par_dev->name at ffff88039cb264c0
> > [ 60.316706] pp_release: kfree(ffff88039cb264c0)
> > [ 60.316714] ==========================================================
> > [ 60.316722] BUG: Double free or freeing an invalid pointer
> > [ 60.316731] Unexpected shadow byte: 0xFB
> > [ 60.316801] Object at ffff88039cb264c0, in cache kmalloc-32 size: 32
> > [ 60.316813] Allocated:
> > [ 60.316824] PID = 1695
> > [ 60.316869] Freed:
> > [ 60.316880] PID = 1695
> > [ 60.316935] ==========================================================
> > CCing Andy Lutomirski because I think this is what broke vmapped stacks
> > for me - after applying this patch, vmapped stacks worked for me.
> > Previously, I got oopses (and lockups) caused by area->pages being
> > 0x400000000 in __vunmap(), with area->pages being allocated in the kmalloc
> > area.
> That's an odd symptom. I assume that what's happening is that the
> pages array is being freed early by the extra kfree in here and then
> getting corrupted.
Well, as far as I can tell, there are two ways to reach that.
Obvious first way, but a pretty tight race:
Task A: free(name)
Task B: allocate area->pages in same place
Task A: second free(name), releasing area->pages
Second way (if the SLAB allocator, which I'm using, is used):
Task A: free(name), appends the object to ac->entry in ___cache_free()
Task A: second free(name), appends the object to ac->entry again
Task B: ____cache_alloc() returns object from array cache
Task C: ____cache_alloc() returns same object again
So then the same memory would be used by two separate objects?
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