[PATCH 1/1] mtd: ubi: skip programming unused bits in ubi headers

[Cheng Ming Lin]

Hi Miquel,

Miquel Raynal <miquel.raynal at bootlin.com> 於 2025年11月6日 週四 下午5:10寫道：
>
> Hello,
>
> On 06/11/2025 at 13:49:40 +08, Cheng Ming Lin <linchengming884 at gmail.com> wrote:
>
> > From: Cheng Ming Lin <chengminglin at mxic.com.tw>
> >
> > This patch prevents unnecessary programming of bits in ec_hdr and
> > vid_hdr that are not used or read during normal UBI operation. These
> > unused bits are typcially already set to 1 in erased flash and do not
> > need to be explicitly programmed to 0 if they are not used.
> >
> > Programming such unused areas offers no functional benefit and may
> > result in unnecessary flash wear, reducing the overall lifetime of the
> > device. By skipping these writes, we preserve the flash state as much as
> > possible and minimize wear caused by redundant operations.
> >
> > This change ensures that only necessary fields are written when preparing
> > UBI headers, improving flash efficiency without affecting functionality.
> >
> > Additionally, the Kioxia TC58NVG1S3HTA00 datasheet (page 63) also notes
> > that continuous program/erase cycling with a high percentage of '0' bits
> > in the data pattern can accelerate block endurance degradation.
> > This further supports avoiding large 0x00 patterns.
> >
> > Link: https://europe.kioxia.com/content/dam/kioxia/newidr/productinfo/datasheet/201910/DST_TC58NVG1S3HTA00-TDE_EN_31442.pdf
> >
> > Signed-off-by: Cheng Ming Lin <chengminglin at mxic.com.tw>
>
> Thanks for this very clear and detailed commit log, as well as for the
> well written cover letter. I am personally fine with the overall idea of
> clearing these unused bits to 1. Yet, I have one concern regarding the
> implementation, please see below.
>
> > ---
> >  drivers/mtd/ubi/io.c | 7 +++++++
> >  1 file changed, 7 insertions(+)
> >
> > diff --git a/drivers/mtd/ubi/io.c b/drivers/mtd/ubi/io.c
> > index a4999bce4..c21242a14 100644
> > --- a/drivers/mtd/ubi/io.c
> > +++ b/drivers/mtd/ubi/io.c
> > @@ -868,6 +868,8 @@ int ubi_io_write_ec_hdr(struct ubi_device *ubi, int pnum,
> >               return -EROFS;
> >       }
> >
> > +     memset((char *)ec_hdr + UBI_EC_HDR_SIZE, 0xFF, ubi->ec_hdr_alsize - UBI_EC_HDR_SIZE);
> > +
> >       err = ubi_io_write(ubi, ec_hdr, pnum, 0, ubi->ec_hdr_alsize);
> >       return err;
> >  }
> > @@ -1150,6 +1152,11 @@ int ubi_io_write_vid_hdr(struct ubi_device *ubi, int pnum,
> >               return -EROFS;
> >       }
> >
> > +     if (ubi->vid_hdr_shift)
> > +             memset((char *)p, 0xFF, ubi->vid_hdr_alsize - UBI_VID_HDR_SIZE);
> > +     else
> > +             memset((char *)p + UBI_VID_HDR_SIZE, 0xFF, ubi->vid_hdr_alsize - UBI_VID_HDR_SIZE);
>
> Here I am reaching the limits of my UBI knowledge, so I would prefer
> Richard to (in)validate what I am saying, but AFAIU, the VID header can
> be literally anywhere in the page, not just at the start or end of a
> subpage, so in the vid_hdr_shift I would expect some extra maths to
> happen, no?

I understand your point now. If the VID header is not guaranteed to be
at the start or end of a subpage, then yes, my current logic needs to be
reworked to cover that case.

>
> Here is an excerpt of the main comment at the top of the io.c file:
>
>     * As it was noted above, the VID header may start at a non-aligned
>     * offset. For example, in case of a 2KiB page NAND flash with a 512
>     * bytes sub-page, the VID header may reside at offset 1984 which is
>     * the last 64 bytes of the * last sub-page (EC header is always at
>     * offset zero).
>
> I am not sure this is super common today though.
>
> Thanks,
> Miquèl

Thanks,
Cheng Ming Lin