[PATCH] mtd: nand: omap: save Bad-Block-Table (BBT) on device
ezequiel at vanguardiasur.com.ar
ezequiel at vanguardiasur.com.ar
Wed Jul 23 13:27:46 PDT 2014
(Brian, correct me if I'm wrong here, you're the BBT expert).
On 23 Jul 04:26 PM, Gupta, Pekon wrote:
> >From: Ezequiel Garcia [mailto:ezequiel at vanguardiasur.com.ar]
> >>On 23 Jul 05:24 PM, Pekon Gupta wrote:
> >> This patch makes OMAP NAND driver to
> >> - save Bad-Block-Table (BBT) on NAND Flash device
> >> - scan on device BBT during probe
> >>
> >
> >Doesn't this break backward compatibility? Please correct me if I'm wrong
> >here, but if I apply this patch, and boot with my current NAND flash
> >contents, the kernel won't have any place to store the BBT (assuming
> >there are no blocks reserved).
>
> Good point. I'll rather like your opinion to judge my below understanding
> as you were recently involved in some NAND BBT features additions..
>
> When bbt_options "NAND_BBT_USE_FLASH" is enabled, default BBT
> options will be used which are:
>
> $KERNEL/drivers/mtd/nand_bbt.c
> static struct nand_bbt_descr bbt_main_descr = {
> .options = NAND_BBT_LASTBLOCK | NAND_BBT_CREATE | NAND_BBT_WRITE
> | NAND_BBT_2BIT | NAND_BBT_VERSION | NAND_BBT_PERCHIP,
>
> As default options have NAND_BBT_CREATE and NAND_BBT_WRITE,
> so kernel will try to reserve erase-blocks for main-BBT and mirror-BBT
> towards end of NAND device.
>
> - Case-1: If there is un-allocated space (not allocated to any partition)
> at end of Flash device then it will be used. And there is no problem.
>
Yes, so far, so good.
> - Case-2: If there is no free space towards the end of flash, then ...
> As per my understanding, the create_bbt() would try scanning whole
> NAND to find empty blocks and then it creates BBT wherever it finds
> empty blocks. And those blocks are marked as BAD with BBT signature
> to prevent getting erased or over-written by any user-data.
>
OK, I just went through the BBT code, trying to see if I was missing
something. I can't see any place where the kernel scans the device
and searches for empty space for the BBT.
Instead, what create_bbt() seem to do is scan the whole device, searching
for bad blocks to fill an in-memory BBT. I presume that if I have some
blocks marked as bad in the OOB region, they are identified as bad
and the BBT is filled.
I think that write_bbt() is where the (previously created, in-memory) BBT
is written to flash. It goes like this:
write_bbt()
{
[..]
/*
* Automatic placement of the bad block table. Search direction
* top -> down?
*/
if (td->options & NAND_BBT_LASTBLOCK) {
startblock = numblocks * (chip + 1) - 1;
dir = -1;
} else {
startblock = chip * numblocks;
dir = 1;
}
for (i = 0; i < td->maxblocks; i++) {
int block = startblock + dir * i;
/* Check, if the block is bad */
switch (bbt_get_entry(this, block)) {
case BBT_BLOCK_WORN:
case BBT_BLOCK_FACTORY_BAD:
continue;
}
page = block <<
(this->bbt_erase_shift - this->page_shift);
/* Check, if the block is used by the mirror table */
if (!md || md->pages[chip] != page)
goto write;
}
pr_err("No space left to write bad block table\n");
return -ENOSPC;
[..]
}
which fails if there's no room left for the BBT. This will happen on every
boot, so it's not an ideal situation.
> Is my understanding correct?
> If yes, then this will not break backward compatibility, as on upgrading
> the kernel new BBT will be automatically written on first boot. And
> it will be used in subsequent boots.
> Need feedbacks ...
>
In fact, you do have a simple way to solve this. Just support BBT through
the "nand-on-flash-bbt" devicetree property, so a user can tell if his flash
has a BBT or not. See pxa3xx-nand.c, which should be correct.
--
Ezequiel Garcia, VanguardiaSur
www.vanguardiasur.com.ar
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