[PATCH] UBI: Remaining typos and comments cleanups

Shinya Kuribayashi shinya.kuribayashi.px at renesas.com
Wed May 5 23:42:05 EDT 2010


Signed-off-by: Shinya Kuribayashi <shinya.kuribayashi.px at renesas.com>
---
  drivers/mtd/ubi/io.c   |    2 +-
  drivers/mtd/ubi/vtbl.c |    4 ++--
  2 files changed, 3 insertions(+), 3 deletions(-)

diff --git a/drivers/mtd/ubi/io.c b/drivers/mtd/ubi/io.c
index 016ec13..cd0bf57 100644
--- a/drivers/mtd/ubi/io.c
+++ b/drivers/mtd/ubi/io.c
@@ -64,7 +64,7 @@
   * device, e.g., make @ubi->min_io_size = 512 in the example above?
   *
   * A: because when writing a sub-page, MTD still writes a full 2K page but the
- * bytes which are no relevant to the sub-page are 0xFF. So, basically, writing
+ * bytes which are not relevant to the sub-page are 0xFF. So, basically, writing
   * 4x512 sub-pages is 4 times slower than writing one 2KiB NAND page. Thus, we
   * prefer to use sub-pages only for EV and VID headers.
   *
diff --git a/drivers/mtd/ubi/vtbl.c b/drivers/mtd/ubi/vtbl.c
index cd90ff3..14c10be 100644
--- a/drivers/mtd/ubi/vtbl.c
+++ b/drivers/mtd/ubi/vtbl.c
@@ -414,7 +414,7 @@ static struct ubi_vtbl_record *process_lvol(struct ubi_device *ubi,
  	 * 0 contains more recent information.
  	 *
  	 * So the plan is to first check LEB 0. Then
-	 * a. if LEB 0 is OK, it must be containing the most resent data; then
+	 * a. if LEB 0 is OK, it must be containing the most recent data; then
  	 *    we compare it with LEB 1, and if they are different, we copy LEB
  	 *    0 to LEB 1;
  	 * b. if LEB 0 is corrupted, but LEB 1 has to be OK, and we copy LEB 1
@@ -848,7 +848,7 @@ int ubi_read_volume_table(struct ubi_device *ubi, struct ubi_scan_info *si)
  		goto out_free;
  
  	/*
-	 * Get sure that the scanning information is consistent to the
+	 * Make sure that the scanning information is consistent to the
  	 * information stored in the volume table.
  	 */
  	err = check_scanning_info(ubi, si);
-- 
1.7.1




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