K9F5608U0B-YIB0000: 528 byte in page, or 512?

Charles Manning manningc2 at actrix.gen.nz
Wed Apr 23 16:32:07 EDT 2003


[snip]
> > >
> > > I understand that page it is necessary to write, but what
> > > bring the first image: chain on 512+512.... or 512+16 free +
> > > 512+16 free...
> > >
> > > As even so write? :-) (to hrdware-level)
> >
> > Please read http://linux-mtd.infraded.org/tech/nand.html
>
> I read, and don't find answer.
>
> 1) make jffs2 image: correct erase block-size for NAND (512+16
> page x 32) is 0x4200 or (512 page x 32) 0x4000?

The eraseure size is 0x4000. 
>
> 2) for writing jffs2 image to NAND use only 512byte space on each
> page, or 512+16?

The 512-byte part is written by the write function and the 16 bit "spare" or 
"out of band"  area is written with the write_oob function.

-- Charles






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