[PATCH v4] scsi: ufs: Cleanup completed request without interrupt notification

Bart Van Assche bvanassche at acm.org
Fri Jul 31 12:51:55 EDT 2020


On 2020-07-31 01:00, Can Guo wrote:
> AFAIK, sychronization of scsi_done is not a problem here, because scsi
> layer
> use the atomic state, namely SCMD_STATE_COMPLETE, of a scsi cmd to prevent
> the concurrency of abort and real completion of it.
> 
> Check func scsi_times_out(), hope it helps.
> 
> enum blk_eh_timer_return scsi_times_out(struct request *req)
> {
> ...
>         if (rtn == BLK_EH_DONE) {
>                 /*
>                  * Set the command to complete first in order to prevent
> a real
>                  * completion from releasing the command while error
> handling
>                  * is using it. If the command was already completed,
> then the
>                  * lower level driver beat the timeout handler, and it
> is safe
>                  * to return without escalating error recovery.
>                  *
>                  * If timeout handling lost the race to a real
> completion, the
>                  * block layer may ignore that due to a fake timeout
> injection,
>                  * so return RESET_TIMER to allow error handling another
> shot
>                  * at this command.
>                  */
>                 if (test_and_set_bit(SCMD_STATE_COMPLETE, &scmd->state))
>                         return BLK_EH_RESET_TIMER;
>                 if (scsi_abort_command(scmd) != SUCCESS) {
>                         set_host_byte(scmd, DID_TIME_OUT);
>                         scsi_eh_scmd_add(scmd);
>                 }
>         }
> }

I am familiar with this mechanism. My concern is that both the regular
completion path and the abort handler must call scsi_dma_unmap() before
calling cmd->scsi_done(cmd). I don't see how
test_and_set_bit(SCMD_STATE_COMPLETE, &scmd->state) could prevent that
the regular completion path and the abort handler call scsi_dma_unmap()
concurrently since both calls happen before the SCMD_STATE_COMPLETE bit
is set?

Thanks,

Bart.



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