[PATCH 2/3] of: irq: make callers of of_irq_parse_one() release the device node

Geert Uytterhoeven geert at linux-m68k.org
Wed Mar 1 23:49:44 PST 2023


Hi Jean-Jacques,

Thanks for your patch!

On Wed, Mar 1, 2023 at 7:53 PM Jean-Jacques Hiblot
<jjhiblot at traphandler.com> wrote:
> of_irq_parse_one() does a get() on the device node returned in out_irq->np.
> Callers of of_irq_parse_one() must do a put() when they are done with it.

What does "be done with it" really mean here?

> Signed-off-by: Jean-Jacques Hiblot <jjhiblot at traphandler.com>

> --- a/arch/arm/mach-shmobile/regulator-quirk-rcar-gen2.c
> +++ b/arch/arm/mach-shmobile/regulator-quirk-rcar-gen2.c
> @@ -184,6 +184,7 @@ static int __init rcar_gen2_regulator_quirk(void)
>                         kfree(quirk);
>                         continue;
>                 }
> +               of_node_put(argsa->np);

The quirk object, which is a container of argsa, is still used below,
and stored in a linked list.  I agree argsa->np is not dereferenced,
but the pointer itself is still compared to other pointers.
IIUIC, calling of_node_put() might cause the reference count to drop to
zero, and the underlying struct node object to be deallocated.
So when a future reference to the same DT node will be taken, a new
struct node object will be allocated, and the pointer comparison below
will fail?

Or am I missing something?

Gr{oetje,eeting}s,

                        Geert

-- 
Geert Uytterhoeven -- There's lots of Linux beyond ia32 -- geert at linux-m68k.org

In personal conversations with technical people, I call myself a hacker. But
when I'm talking to journalists I just say "programmer" or something like that.
                                -- Linus Torvalds



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