[PATCH v2] arm64: Expand the static memblock memory table
Anshuman Khandual
anshuman.khandual at arm.com
Fri Jun 3 03:54:37 PDT 2022
On 5/27/22 14:26, Zhouguanghui (OS Kernel) wrote:
> Hi Anshuman,
>
> 在 2022/5/18 12:40, Anshuman Khandual 写道:
>> Hi Zhou,
>>
>> A small nit.
>>
>> This changes generic memblock to accommodate arm64 specific scenario.
>> Keeping the subject line as 'mm/memblock: ...' might be better.
>>
>
> I will add memblock to the subject line.
>
>> On 5/17/22 17:13, Zhou Guanghui wrote:
>>> In a system using HBM, a multi-bit ECC error occurs, and the BIOS
>>> saves the corresponding area (for example, 2 MB). When the system
>>> restarts next time, these areas are isolated and not reported or
>>> reported as EFI_UNUSABLE_MEMORY. Both of them lead to an increase
>>
>> Which cases dont get reported rather than as EFI_UNUSABLE_MEMORY ? Is
>> this supported on arm64 platform via mainline kernel ?
>>
>
> The BIOS determines how to report the memory area that cannot be used to
> the kernel. Do not report the memory area to the kernel or inform the
> kernel that the memory area is unusable.
Right, but just curious whether there are real systems in the field with
this feature running mainline kernel ? OR this is just being future proof.
>
>>> in the number of memblocks, whereas EFI_UNUSABLE_MEMORY leads to
>>> a larger number of memblocks.
>>>
>>> For example, if the EFI_UNUSABLE_MEMORY type is reported:
>>> ...
>>> memory[0x92] [0x0000200834a00000-0x0000200835bfffff], 0x0000000001200000 bytes on node 7 flags: 0x0
>>> memory[0x93] [0x0000200835c00000-0x0000200835dfffff], 0x0000000000200000 bytes on node 7 flags: 0x4
>>> memory[0x94] [0x0000200835e00000-0x00002008367fffff], 0x0000000000a00000 bytes on node 7 flags: 0x0
>>> memory[0x95] [0x0000200836800000-0x00002008369fffff], 0x0000000000200000 bytes on node 7 flags: 0x4
>>> memory[0x96] [0x0000200836a00000-0x0000200837bfffff], 0x0000000001200000 bytes on node 7 flags: 0x0
>>> memory[0x97] [0x0000200837c00000-0x0000200837dfffff], 0x0000000000200000 bytes on node 7 flags: 0x4
>>> memory[0x98] [0x0000200837e00000-0x000020087fffffff], 0x0000000048200000 bytes on node 7 flags: 0x0
>>> memory[0x99] [0x0000200880000000-0x0000200bcfffffff], 0x0000000350000000 bytes on node 6 flags: 0x0
>>> memory[0x9a] [0x0000200bd0000000-0x0000200bd01fffff], 0x0000000000200000 bytes on node 6 flags: 0x4
>>> memory[0x9b] [0x0000200bd0200000-0x0000200bd07fffff], 0x0000000000600000 bytes on node 6 flags: 0x0
>>> memory[0x9c] [0x0000200bd0800000-0x0000200bd09fffff], 0x0000000000200000 bytes on node 6 flags: 0x4
>>> memory[0x9d] [0x0000200bd0a00000-0x0000200fcfffffff], 0x00000003ff600000 bytes on node 6 flags: 0x0
>>> memory[0x9e] [0x0000200fd0000000-0x0000200fd01fffff], 0x0000000000200000 bytes on node 6 flags: 0x4
>>> memory[0x9f] [0x0000200fd0200000-0x0000200fffffffff], 0x000000002fe00000 bytes on node 6 flags: 0x0
>>
>> Got it.
>>
>>> ...
>>>
>>> If the size of the init memblock regions is exceeded before the
>>> array size can be resized, the excess memory will be lost.
>>
>> Could you please elaborate more on why additional memblock regions can
>> not be accommodated via memblock array resizing ?
>>
>
> As described in the memblock_double_array function: We don't allow
> resizing until we know about the reserved regions of memory that aren'
> not suitable for allocation.
>
>>>
>>> Signed-off-by: Zhou Guanghui <zhouguanghui1 at huawei.com>
>>> ---
>>> arch/arm64/include/asm/memory.h | 9 +++++++++
>>> mm/memblock.c | 14 +++++++++-----
>>> 2 files changed, 18 insertions(+), 5 deletions(-)
>>>
>>> diff --git a/arch/arm64/include/asm/memory.h b/arch/arm64/include/asm/memory.h
>>> index 0af70d9abede..eda61c0389c4 100644
>>> --- a/arch/arm64/include/asm/memory.h
>>> +++ b/arch/arm64/include/asm/memory.h
>>> @@ -364,6 +364,15 @@ void dump_mem_limit(void);
>>> # define INIT_MEMBLOCK_RESERVED_REGIONS (INIT_MEMBLOCK_REGIONS + NR_CPUS + 1)
>>> #endif
>>>
>>> +/*
>>> + * memory regions which marked with flag MEMBLOCK_NOMAP may divide a continuous
>>> + * memory block into multiple parts. As a result, the number of memory regions
>>> + * is large.
>>> + */
>>> +#ifdef CONFIG_EFI
>>
>> Could not memblock regions tagged with MEMBLOCK_NOMAP flag not present
>> on non-EFI systems ? Just wondering, are there not some other scenarios
>> which will also require expanded static memblock array.
>
> Systems using devicetree can also have "no-map" memory. However, in this
> case, the expanded static memblock array is required only when a large
> number of such no-map reserved memories are manually added. I don't know
> if any users will do that.
>
> Documentation/devicetree/bindings/reserved-memory/reserved-memory.yaml
>
> As to whether other scenarios also require expanded static memblock
> arrays, I really don't know.
In that case could this comment here be more specific about this increased
static array size, being applicable only for MEMBLOCK_NOMAP regions on EFI
system with EFI_UNUSABLE_MEMORY tagging support. Is there an way to narrow
this down further wrt EFI_UNUSABLE_MEMORY, rather than blanket EFI ?
+/*
+ * memory regions which marked with flag MEMBLOCK_NOMAP may divide a continuous
+ * memory block into multiple parts. As a result, the number of memory regions
+ * is large.
+ */
+#ifdef CONFIG_EFI
+#define INIT_MEMBLOCK_MEMORY_REGIONS 1024
+#endif
+
>
>>
>>> +#define INIT_MEMBLOCK_MEMORY_REGIONS 1024
>>> +#endif
>>> +
>>> #include <asm-generic/memory_model.h>
>>>
>>> #endif /* __ASM_MEMORY_H */
>>> diff --git a/mm/memblock.c b/mm/memblock.c
>>> index e4f03a6e8e56..7c63571a69d7 100644
>>> --- a/mm/memblock.c
>>> +++ b/mm/memblock.c
>>> @@ -29,6 +29,10 @@
>>> # define INIT_MEMBLOCK_RESERVED_REGIONS INIT_MEMBLOCK_REGIONS
>>> #endif
>>>
>>> +#ifndef INIT_MEMBLOCK_MEMORY_REGIONS
>>> +#define INIT_MEMBLOCK_MEMORY_REGIONS INIT_MEMBLOCK_REGIONS
>>> +#endif
>>
>> Why create an additional macro INIT_MEMBLOCK_MEMORY_REGIONS ? Why cannot
>> INIT_MEMBLOCK_REGIONS be defined in the platform directly like the other
>> macro INIT_MEMBLOCK_RESERVED_REGIONS ?
>>
>
> The number of reserved memblocks does not need to be increased.
Got it.
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