[PATCH 04/18] alpha: Override READ_ONCE() with barriered implementation
Arnd Bergmann
arnd at arndb.de
Thu Jul 2 06:08:41 EDT 2020
On Thu, Jul 2, 2020 at 11:48 AM Will Deacon <will at kernel.org> wrote:
> On Thu, Jul 02, 2020 at 10:32:39AM +0100, Mark Rutland wrote:
> > On Tue, Jun 30, 2020 at 06:37:20PM +0100, Will Deacon wrote:
> > > -#define read_barrier_depends() __asm__ __volatile__("mb": : :"memory")
> > > +#define __smp_load_acquire(p) \
> > > +({ \
> > > + __unqual_scalar_typeof(*p) ___p1 = \
> > > + (*(volatile typeof(___p1) *)(p)); \
> > > + compiletime_assert_atomic_type(*p); \
> > > + ___p1; \
> > > +})
> >
> > Sorry if I'm being thick, but doesn't this need a barrier after the
> > volatile access to provide the acquire semantic?
> >
> > IIUC prior to this commit alpha would have used the asm-generic
> > __smp_load_acquire, i.e.
> >
> > | #ifndef __smp_load_acquire
> > | #define __smp_load_acquire(p) \
> > | ({ \
> > | __unqual_scalar_typeof(*p) ___p1 = READ_ONCE(*p); \
> > | compiletime_assert_atomic_type(*p); \
> > | __smp_mb(); \
> > | (typeof(*p))___p1; \
> > | })
> > | #endif
I also have a question that I didn't dare ask when the same
code came up before (I guess it's also what's in the kernel today):
With the cast to 'typeof(*p)' at the end, doesn't that mean we
lose the effect of __unqual_scalar_typeof() again, so any "volatile"
pointer passed into __READ_ONCE_SCALAR() or
__smp_load_acquire() still leads to a volatile load of the original
variable, plus another volatile access to ___p1 after
spilling it to the stack as a non-volatile variable?
I hope I'm missing something obvious here.
Arnd
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