arm64/v4.16-rc1: KASAN: use-after-free Read in finish_task_switch
Mathieu Desnoyers
mathieu.desnoyers at efficios.com
Thu Feb 15 16:02:42 PST 2018
----- On Feb 15, 2018, at 5:08 PM, Mathieu Desnoyers mathieu.desnoyers at efficios.com wrote:
> ----- On Feb 15, 2018, at 1:21 PM, Will Deacon will.deacon at arm.com wrote:
>
>> On Thu, Feb 15, 2018 at 05:47:54PM +0100, Peter Zijlstra wrote:
>>> On Thu, Feb 15, 2018 at 02:22:39PM +0000, Will Deacon wrote:
>>> > Instead, we've come up with a more plausible sequence that can in theory
>>> > happen on a single CPU:
>>> >
>>> > <task foo calls exit()>
>>> >
>>> > do_exit
>>> > exit_mm
>>>
>>> If this is the last task of the process, we would expect:
>>>
>>> mm_count == 1
>>> mm_users == 1
>>>
>>> at this point.
>>>
>>> > mmgrab(mm); // foo's mm has count +1
>>> > BUG_ON(mm != current->active_mm);
>>> > task_lock(current);
>>> > current->mm = NULL;
>>> > task_unlock(current);
>>>
>>> So the whole active_mm is basically the last 'real' mm, and its purpose
>>> is to avoid switch_mm() between user tasks and kernel tasks.
>>>
>>> A kernel task has !->mm. We do this by incrementing mm_count when
>>> switching from user to kernel task and decrementing when switching from
>>> kernel to user.
>>>
>>> What exit_mm() does is change a user task into a 'kernel' task. So it
>>> should increment mm_count to mirror the context switch. I suspect this
>>> is what the mmgrab() in exit_mm() is for.
>>>
>>> > <irq and ctxsw to kthread>
>>> >
>>> > context_switch(prev=foo, next=kthread)
>>> > mm = next->mm;
>>> > oldmm = prev->active_mm;
>>> >
>>> > if (!mm) { // True for kthread
>>> > next->active_mm = oldmm;
>>> > mmgrab(oldmm); // foo's mm has count +2
>>> > }
>>> >
>>> > if (!prev->mm) { // True for foo
>>> > rq->prev_mm = oldmm;
>>> > }
>>> >
>>> > finish_task_switch
>>> > mm = rq->prev_mm;
>>> > if (mm) { // True (foo's mm)
>>> > mmdrop(mm); // foo's mm has count +1
>>> > }
>>> >
>>> > [...]
>>> >
>>> > <ctxsw to task bar>
>>> >
>>> > context_switch(prev=kthread, next=bar)
>>> > mm = next->mm;
>>> > oldmm = prev->active_mm; // foo's mm!
>>> >
>>> > if (!prev->mm) { // True for kthread
>>> > rq->prev_mm = oldmm;
>>> > }
>>> >
>>> > finish_task_switch
>>> > mm = rq->prev_mm;
>>> > if (mm) { // True (foo's mm)
>>> > mmdrop(mm); // foo's mm has count +0
>>>
>>> The context switch into the next user task will then decrement. At this
>>> point foo no longer has a reference to its mm, except on the stack.
>>>
>>> > }
>>> >
>>> > [...]
>>> >
>>> > <ctxsw back to task foo>
>>> >
>>> > context_switch(prev=bar, next=foo)
>>> > mm = next->mm;
>>> > oldmm = prev->active_mm;
>>> >
>>> > if (!mm) { // True for foo
>>> > next->active_mm = oldmm; // This is bar's mm
>>> > mmgrab(oldmm); // bar's mm has count +1
>>> > }
>>> >
>>> >
>>> > [return back to exit_mm]
>>>
>>> Enter mm_users, this counts the number of tasks associated with the mm.
>>> We start with 1 in mm_init(), and when it drops to 0, we decrement
>>> mm_count. Since we also start with mm_count == 1, this would appear
>>> consistent.
>>>
>>> mmput() // --mm_users == 0, which then results in:
>>>
>>> > mmdrop(mm); // foo's mm has count -1
>>>
>>> In the above case, that's the very last reference to the mm, and since
>>> we started out with mm_count == 1, this -1 makes 0 and we do the actual
>>> free.
>>>
>>> > At this point, we've got an imbalanced count on the mm and could free it
>>> > prematurely as seen in the KASAN log.
>>>
>>> I'm not sure I see premature. At this point mm_users==0, mm_count==0 and
>>> we freed mm and there is no further use of the on-stack mm pointer and
>>> foo no longer has a pointer to it in either ->mm or ->active_mm. It's
>>> well and proper dead.
>>>
>>> > A subsequent context-switch away from foo would therefore result in a
>>> > use-after-free.
>>>
>>> At the above point, foo no longer has a reference to mm, we cleared ->mm
>>> early, and the context switch to bar cleared ->active_mm. The switch
>>> back into foo then results with foo->active_mm == bar->mm, which is
>>> fine.
>>
>> Bugger, you're right. When we switch off foo after freeing the mm, we'll
>> actually access it's active mm which points to bar's mm. So whilst this
>> can explain part of the kasan splat, it doesn't explain the actual
>> use-after-free.
>>
>> More head-scratching required :(
>
> My current theory: do_exit() gets preempted after having set current->mm
> to NULL, and after having issued mmput(), which brings the mm_count down
> to 0. Unfortunately, if the scheduler switches from a userspace thread
> to a kernel thread, context_switch() loads prev->active_mm which still
> points to the now-freed mm, mmgrab the mm, and eventually does mmdrop
> in finish_task_switch().
>
> If my understanding is correct, the following patch should help. The idea
> is to keep a reference on the mm_count until after we are sure the scheduler
> cannot schedule the task anymore. What I'm not sure is where exactly in
> do_exit() are we sure the task cannot ever be preempted anymore ?
>
Actually, it's the preempt_disable() at the end of do_exit() I was looking
for. The following patch moves the mmdrop() right after preempte_disable.
In my previous patch, the mmdrop() after do_task_dead (which is noreturn)
was rather dumb (leak).
diff --git a/kernel/exit.c b/kernel/exit.c
index 995453d..2804655 100644
--- a/kernel/exit.c
+++ b/kernel/exit.c
@@ -764,6 +764,7 @@ void __noreturn do_exit(long code)
{
struct task_struct *tsk = current;
int group_dead;
+ struct mm_struct *mm;
profile_task_exit(tsk);
kcov_task_exit(tsk);
@@ -849,6 +850,10 @@ void __noreturn do_exit(long code)
tsk->exit_code = code;
taskstats_exit(tsk, group_dead);
+ mm = current->mm;
+ if (mm)
+ mmgrab(mm);
+
exit_mm();
if (group_dead)
@@ -913,6 +918,8 @@ void __noreturn do_exit(long code)
check_stack_usage();
preempt_disable();
+ if (mm)
+ mmdrop(mm);
if (tsk->nr_dirtied)
__this_cpu_add(dirty_throttle_leaks, tsk->nr_dirtied);
exit_rcu();
--
Mathieu Desnoyers
EfficiOS Inc.
http://www.efficios.com
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