[PATCH v8 5/8] arm64: Use of_cpu_node_to_id helper for CPU topology parsing
Will Deacon
will.deacon at arm.com
Tue Oct 17 09:11:40 PDT 2017
On Tue, Oct 17, 2017 at 04:24:23PM +0100, Mark Rutland wrote:
> On Tue, Oct 10, 2017 at 11:33:00AM +0100, Suzuki K Poulose wrote:
> > Make use of the new generic helper to convert an of_node of a CPU
> > to the logical CPU id in parsing the topology.
> >
> > Cc: Catalin Marinas <catalin.marinas at arm.com>
> > Cc: Leo Yan <leo.yan at linaro.org>
> > Cc: Will Deacon <will.deacon at arm.com>
> > Cc: Mark Rutland <mark.rutland at arm.com>
> > Signed-off-by: Suzuki K Poulose <suzuki.poulose at arm.com>
>
> This looks sane to me, but it will need an ack from Will or Catalin.
>
> FWIW:
>
> Acked-by: Mark Rutland <mark.rutland at arm.com>
>
> Thanks,
> Mark.
>
> > ---
> > arch/arm64/kernel/topology.c | 16 ++++++----------
> > 1 file changed, 6 insertions(+), 10 deletions(-)
> >
> > diff --git a/arch/arm64/kernel/topology.c b/arch/arm64/kernel/topology.c
> > index 8d48b233e6ce..21868530018e 100644
> > --- a/arch/arm64/kernel/topology.c
> > +++ b/arch/arm64/kernel/topology.c
> > @@ -37,18 +37,14 @@ static int __init get_cpu_for_node(struct device_node *node)
> > if (!cpu_node)
> > return -1;
> >
> > - for_each_possible_cpu(cpu) {
> > - if (of_get_cpu_node(cpu, NULL) == cpu_node) {
> > - topology_parse_cpu_capacity(cpu_node, cpu);
> > - of_node_put(cpu_node);
> > - return cpu;
> > - }
> > - }
> > -
> > - pr_crit("Unable to find CPU node for %pOF\n", cpu_node);
> > + cpu = of_cpu_node_to_id(cpu_node);
> > + if (cpu >= 0)
> > + topology_parse_cpu_capacity(cpu_node, cpu);
> > + else
> > + pr_crit("Unable to find CPU node for %pOF\n", cpu_node);
> >
> > of_node_put(cpu_node);
This of_node_put is confusing me. Since of_cpu_node_to_id appears to be
balanced with its use of the node refcount, is this one intended to pair
with the earlier call to of_parse_phandle? If so, does that mainline is
currently broken here because it doesn't drop the refcount twice for the
matching node? Or do we need to return with that held?
Will
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