[PATCH v2 7/7] ARM: KVM: Unlock vgic-v3 support

Peter Maydell peter.maydell at linaro.org
Wed Sep 7 07:20:14 PDT 2016


On 7 September 2016 at 13:58, Christoffer Dall
<christoffer.dall at linaro.org> wrote:
> On Wed, Sep 07, 2016 at 11:48:52AM +0100, Vladimir Murzin wrote:
>> On 06/09/16 17:55, Christoffer Dall wrote:
>> > On Tue, Sep 06, 2016 at 02:23:16PM +0100, Vladimir Murzin wrote:
>> >>
>> >> Sorry, missed this one
>> >>
>> >> On 05/09/16 12:29, Christoffer Dall wrote:
>> >>>>
>> >>>>> +static bool __hyp_text __has_useable_gicv3_cpuif(void)
>> >>>>> +{
>> >>>>> +       if (IS_ENABLED(CONFIG_ARM_GIC_V3) && (read_sysreg(ID_PFR1) >> 28))
>> >>> Do we have a define for bit 28 we could use?
>> >>
>> >> I'll check it.
>> >>
>> >>>
>> >>> Does this actually work on all v7 boards?  The v7 ARM ARM seems to state
>> >>> that this bitfield is Reserved, UNK.  Does that somehow mean 'is going
>> >>> to be zero'?
>> >>
>> >> It is how v7ARM ARM I have defines UNK
>> >>
>> >> An abbreviation indicating that software must treat a field as
>> >> containing an UNKNOWN value. Hardware must implement the bit as read as
>> >> 0, or all 0s for a bit field. Software must not rely on the field
>> >> reading as zero.
>> >>
>> >> It seems goes under 'is going to be zero' case, no?
>> >>
>> > The last sentence is disturbing to me, and feels slightly contradicting
>> > itself.  Reading the UNKNOWN description doesn't help much either.
>> >
>> > Perhaps you can ask around internally and figure out what the precise
>> > answer to this is?
>>
>> Since it is kind of implementation dependant thing the precise answer
>> from here hardly help, IMO. We still have non-zero chance to see
>> something scary.
>
> Well, if the precise answer is: This will actually always return 0
> because of X and Y, then your code is fine.

I think the "must not rely on the field reading as zero" wording
in the case of the ID registers is intended to mean "in a
future rev of the architecture we may assign these bits,
and your code mustn't do something that will break if the
bits then read as something other than zero". (And indeed
in v8 bits 28..31 have an assigned meaning.) It doesn't
mean there'll be v7 hardware out there with non-zero
values, because that would be breaking the hardware's part
of the UNKNOWN contract ("must implement the bit as read as 0").

thanks
-- PMM



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