[PATCH] regulator: core: Still free GPIOs using gpio_free()
Mark Brown
broonie at kernel.org
Tue Jul 1 05:11:42 PDT 2014
On Tue, Jul 01, 2014 at 01:06:22PM +0100, Russell King - ARM Linux wrote:
> On Tue, Jul 01, 2014 at 12:55:26PM +0100, Mark Brown wrote:
> > Even though we mostly use GPIO descriptors internally we still use
> > gpio_request_one() to request so we need to pair that with gpio_free() to
> > release the GPIO.
> This doesn't explain the reason... I see the current GPIO code doing this:
> void gpio_free(unsigned gpio)
> {
> gpiod_free(gpio_to_desc(gpio));
> }
> EXPORT_SYMBOL_GPL(gpio_free);
Huh, good point (though it still seems a bit neater to match up the
request and release functions I guess). Linus?
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