[PATCH 1/2] clk: divider: prepare for minimum divider
Stephen Boyd
sboyd at codeaurora.org
Tue Jan 22 13:28:31 EST 2013
On 01/22/13 08:39, Afzal Mohammed wrote:
> diff --git a/drivers/clk/clk-divider.c b/drivers/clk/clk-divider.c
> index a9204c6..0b34992 100644
> --- a/drivers/clk/clk-divider.c
> +++ b/drivers/clk/clk-divider.c
> @@ -236,7 +236,7 @@ EXPORT_SYMBOL_GPL(clk_divider_ops);
>
> static struct clk *_register_divider(struct device *dev, const char *name,
> const char *parent_name, unsigned long flags,
> - void __iomem *reg, u8 shift, u8 width,
> + void __iomem *reg, u8 shift, u8 width, u8 min_div,
> u8 clk_divider_flags, const struct clk_div_table *table,
> spinlock_t *lock)
> {
> @@ -261,6 +261,7 @@ static struct clk *_register_divider(struct device *dev, const char *name,
> div->reg = reg;
> div->shift = shift;
> div->width = width;
> + div->min_div = min_div;
> div->flags = clk_divider_flags;
> div->lock = lock;
> div->hw.init = &init;
> @@ -284,16 +285,17 @@ static struct clk *_register_divider(struct device *dev, const char *name,
> * @reg: register address to adjust divider
> * @shift: number of bits to shift the bitfield
> * @width: width of the bitfield
> + * @min_div: minimum allowable divider value
> * @clk_divider_flags: divider-specific flags for this clock
> * @lock: shared register lock for this clock
> */
> struct clk *clk_register_divider(struct device *dev, const char *name,
> const char *parent_name, unsigned long flags,
> - void __iomem *reg, u8 shift, u8 width,
> + void __iomem *reg, u8 shift, u8 width, u8 min_div,
> u8 clk_divider_flags, spinlock_t *lock)
> {
> return _register_divider(dev, name, parent_name, flags, reg, shift,
> - width, clk_divider_flags, NULL, lock);
> + width, min_div, clk_divider_flags, NULL, lock);
> }
Can you make a new function, clk_register_min_divider(), to avoid
disturbing all users of clock dividers that don't have a minimum? Then
the default can be put into the two registration functions in
clk-divider.c and you don't have to change all clock divider users
across the tree.
--
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