[PATCH v4 1/2] kho: Adopt radix tree for preserved memory tracking
Jason Gunthorpe
jgg at nvidia.com
Mon Jan 12 06:39:04 PST 2026
On Mon, Jan 12, 2026 at 12:15:54PM +0200, Mike Rapoport wrote:
> > + * The tree is traversed using a key that encodes the page's physical address
> > + * (pa) and its order into a single unsigned long value. The encoded key value
> > + * is composed of two parts: the 'order bit' in the upper part and the 'page
> > + * offset' in the lower part.::
> > + *
> > + * +------------+-----------------------------+--------------------------+
> > + * | Page Order | Order Bit | Page Offset |
> > + * +------------+-----------------------------+--------------------------+
> > + * | 0 | ...000100 ... (at bit 52) | pa >> (PAGE_SHIFT + 0) |
> > + * | 1 | ...000010 ... (at bit 51) | pa >> (PAGE_SHIFT + 1) |
> > + * | 2 | ...000001 ... (at bit 50) | pa >> (PAGE_SHIFT + 2) |
> > + * | ... | ... | ... |
> > + * +------------+-----------------------------+--------------------------+
> > + *
> > + * Page Offset:
>
> To me "page offset" reads as offset from somewhere and here it's rather pfn
> on steroids :)
> Also in many places in the kernel "page offset" refers to the offset inside a
> page.
>
> Can't say I can think of a better name, but it feels that it should express
> that this is an address more explicitly.
It is "Shifted Physical Address"
> > + node = phys_to_virt((phys_addr_t)node->table[idx]);
> > + }
> > +
> > + /* Handle the leaf level bitmap (level 0) */
> > + leaf = (struct kho_radix_leaf *)node;
> > + idx = kho_radix_get_index(key, 0);
> > + __clear_bit(idx, leaf->bitmap);
>
> I think I already mentioned it in earlier reviews, but I don't remember any
> response.
>
> How do we approach freeing empty bitmaps and intermediate nodes?
> If we do a few preserve/uppreserve cycles for memory that can be allocated
> and freed in between we might get many unused bitmaps.
Surely this is an error case??
We shouldn't be unpreserving at all in a normal flow?
> My view is that we should free the empty bitmaps, maybe asynchronously.
> The intermediate nodes probably don't take that much memory to bother with
> them.
Telling they are empty would be quite expensive. I think we should not
attempt to clean the tree unless there is a really good reason why we
should have good flows with alot of unpreserving activity.
I think we would be better served to treat the root cause and fixup
what ever is doing preserving/unpreserving loops.
Jason
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