[PATCH 2/2] x86/kexec/64: Forbid kexec when running as an SEV-ES guest
Joerg Roedel
jroedel at suse.de
Thu May 6 11:41:05 PDT 2021
On Thu, May 06, 2021 at 12:42:03PM -0500, Eric W. Biederman wrote:
> I don't understand this.
>
> Fundamentally kexec is about doing things more or less inspite of
> what the firmware is doing.
>
> I don't have any idea what a SEV-ES is. But the normal x86 boot doesn't
> do anything special. Is cross cpu IPI emulation buggy?
Under SEV-ES the normal SIPI-based sequence to re-initialize a CPU does
not work anymore. An SEV-ES guest is a special virtual machine where the
hardware encrypts the guest memory and the guest register state. The
hypervisor can't make any modifications to the guests registers at
runtime. Therefore it also can't emulate a SIPI sequence and reset the
vCPU.
The guest kernel has to reset the vCPU itself and hand it over from the
old kernel to the kexec'ed kernel. This isn't currently implemented and
therefore kexec needs to be disabled when running as an SEV-ES guest.
Implementing this also requires an extension to the guest-hypervisor
protocol (the GHCB Spec[1]) which is only available in version 2. So a
guest running on a hypervisor supporting only version 1 will never
properly support kexec.
> What is the actual problem you are trying to avoid?
Currently, if someone tries kexec in an SEV-ES guest, the kexec'ed
kernel will only be able to bring up the boot CPU, not the others. The
others will wake up with the old kernels CPU state in the new kernels
memory and do undefined things, most likely triple-fault because their
page-table is not existent anymore.
So since kexec currently does not work as expected under SEV-ES, it is
better to hide it until everything is implemented so it can do what the
user expects.
> And yes for a temporary hack the suggestion of putting code into
> machine_kexec_prepare seems much more reasonable so we don't have to
> carry special case infrastructure for the forseeable future.
As I said above, for protocol version 1 it will stay disabled, so it is
not only a temporary hack.
Regards,
Joerg
[1] https://developer.amd.com/wp-content/resources/56421.pdf
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