[PATCH] [RFC] kexec: Fix off-by-one errors in locate_hole()

[Geert Uytterhoeven]

When calling locate_hole() with "hole_size" equal to the size of an
available memory block, it fails to use that memory block.

"end" and "hole_max" point to the last byte within the range, hence
  - "size = end - start" is one less than "hole_size",
  - "hole_base + hole_size" is one more than "hole_max".

Subtract one from "hole_size" when doing the comparison (adding 1 to "size"
could overflow in case of one big range covering the whole address space).

Signed-off-by: Geert Uytterhoeven <geert at linux-m68k.org>
---
Question:
    The code no longer handles the case where "hole_size" is zero.
    Should this be rejected (like is done for a zero "hole_end" at the top
    of the function), or accepted?

 kexec/kexec.c |    4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/kexec/kexec.c b/kexec/kexec.c
index 2b98ef0..eafd6c2 100644
--- a/kexec/kexec.c
+++ b/kexec/kexec.c
@@ -270,7 +270,7 @@ unsigned long locate_hole(struct kexec_info *info,
 		}
 		/* Is there enough space left so we can use it? */
 		size = end - start;
-		if (size >= hole_size) {
+		if (size >= hole_size - 1) {
 			if (hole_end > 0) {
 				hole_base = start;
 				break;
@@ -286,7 +286,7 @@ unsigned long locate_hole(struct kexec_info *info,
 			"0x%lx bytes...\n", hole_size);
 		return ULONG_MAX;
 	}
-	if ((hole_base + hole_size)  > hole_max) {
+	if ((hole_base + hole_size - 1)  > hole_max) {
 		fprintf(stderr, "Could not find a free area of memory below: "
 			"0x%lx...\n", hole_max);
 		return ULONG_MAX;
-- 
1.7.9.5